4-36m^2=0

Solution for 4-36m^2=0 equation:

4-36m^2=0

a = -36; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-36)·4
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-36}=\frac{-24}{-72}
=1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-36}=\frac{24}{-72}
=-1/3
$